`3.overline(87)`

Question

`3.overline(87)` - `2.overline(59)` = ?

Options:

A . 1.20

B . `1.overline(2)`

C . `1.overline(27)`

D . `1.overline(28)`

Answer: Option D

`3.overline(87)` - `2.overline(59)`= (3 + `0.overline(87)` - ( 2 + `0.overline(59)` = `(3 + 87/99 )` - `( 2 + 59/99)`

1 + `(87/99 - 59/99 )` = 1 + `28/99` = `1. overline(28)` .

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