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2f(x)+3f[(4x+5)(x4)]=(x+1)2
Find the value of f(5) if x is a real number not equal to 4.
Options:
A .  -62
B .  1112
C .  442
D .  None of these
Answer: Option D
:
D
Put x=5, 2f(5)+3f(25)=36.
Put x=25, 2f(25)+3f(5)=676.
f(5) = 391.2

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