`2/9` part of the population in a village are males. If 30% of the males are married, the percentage of unmarried
females in the total population is :
Let total population = `x`, Then, number of males = `5/9 x`
Married males = 30% of `5/9 x = (30/100 xx 5/9 x) = x/6`
Married females = `x/6` Number of females = `(x - 5/9 x) = (4x)/(9)`
Unmarried females = `((4x)/(9) - x/6)= (5x)/(18)`
`:.` Required percentage = `((5x)/(18) xx 1/x xx 100)`% = `27 7/9`%
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