27 spherical iron balls of radius 5 cm each are melted and recasted into a big sphere.The radius of the big sphere is _____.
Options:
A. 3 cm
B. 9 cm 
C. 15 cm 
D. 5 cm 

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Answer: Option C
: C

Volumeof the big iron ballwill be equal to the volume of27 small iron balls.
Let the radius of the big sphere be R cm.
Let the radius of the small sphere be
r cm = 5 cm. 43×πR3=27×(43×πr3)

R3=27r3 R=3r=3×5=15 cm.

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