27 spherical iron balls of radius 5 cm each are melted and recasted into a big sphere.The radius of the big sphere is _____.

**Options:**

A. | 3 cm |

B. | 9 cm |

C. | 15 cm |

D. | 5 cm |

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**Answer: Option C**

: C

Volumeof the big iron ballwill be equal to the volume of27 small iron balls.

Let the radius of the big sphere be R cm.

Let the radius of the small sphere be

r cm = 5 cm. ⇒43×πR3=27×(43×πr3)

⇒R3=27r3 R=3r=3×5=15 cm.

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