20 litres of a mixture contains 20% alcohol and the rest water. If 4 litres of water be mixed in it, the percentage of alcohol in the new mixture will be
Options:
A . 12$1/2$%
B . 33$1/3$%
C . 16$2/3$%
D . 25%
Answer: Option C Answer: (c)In 20 litres of mixture,Alcohol = ${20 × 20}/100 = 4 litres$Water = 20 - 4 = 16 litres On adding 4 litres of water, Quantity of water = 16 + 4 = 20 litres Quantity of mixture = 24 litresRequired percent =$4/24 × 100 = 50/3 = 16{2}/3%$
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