Question
12cos−1(1−x1+x)=
Answer: Option B
:
B
Let x=tan2θ⇒θ=tan−1√x
Now, 12cos−1(1−x1+x)
=12cos−1(1−tan2θ1+tan2θ)
=12cos−1cos2θ=2θ2=θ=tan−1√x.
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:
B
Let x=tan2θ⇒θ=tan−1√x
Now, 12cos−1(1−x1+x)
=12cos−1(1−tan2θ1+tan2θ)
=12cos−1cos2θ=2θ2=θ=tan−1√x.
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