10 years ago ,the average age of a family of 4 members was 24 years. Two children having been born)with age difference of 2 years), the present average age of the family is the same. The present age of the youngest child is :
Total age of 4 members, 10 years ago = (24 x 4) years = 96 years
Total age of 4 members now = (96 + 10 x 4) years = 136 years.
Total age of 6 members now + (24 x 6) years = 144 years
Sum of the ages of 2 children = (144 - 136) years = 8 years
Let the age of the younger child be `x` years.
then age of the elder child = (`x` + 2) years
So, ` x + x + 2 = 8` `hArr` = `2x` = 6 `hArr` `x` = 3
`:.` Age of younger child = 3 years.
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