# Time And Work

**Vedic Maths trick to Find Time And Work Problems.**

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Ramesh takes **1hrs** to do a job, Suresh takes **6hrs** to do the same job. How log does it take if both are working together but indipendently to do the same job.

If Ramesh takes **1hrs** to do a job in 1hr.

Then, 1hr = ^{1}/_{1} job.

If Suresh takes **6hrs** to do a job in 1hr.

Then, 1hr = ^{1}/_{6} job.

Now add both the values and inverse them and then we will get_browser

^{6 + 1}/_{6}

So, the result will be

**1 **^{1}/_{6}hr

^{6 + 1}/

_{6}

^{1}/

_{6}hr