# Square root in just 3 second

## Find square root up to '4' digit number.

#####
Find square root of **'5625'**.

### STEP 1 :

First we have to know about these square roots to solve the above value.

Let's say it SQUARELIST -

1^{2} = 1

2^{2} = 4

3^{2} = 9

4^{2} = 16

5^{2} = 25

6^{2} = 36

7^{2} = 49

8^{2} = 64

9^{2} = 81

10^{2} = 100

### STEP 2 :

Now Split **'5625'** from the tens digit like this

##### VALUE ONE = 56 and VALUE TWO = 25

### STEP 3 :

Let's take unit place of VALUE TWO and Compare it with the unt place of above SQUARELIST and find out in which of the 2 SQUARELIST it lies in between.

Those selected SQUARELIST are :

##### 5^{2} = 25 and ^{2} = 0

So, the last digit of the square root value will be either **5**or .

### STEP 4 :

Now we will find VALUE ONE by compareing it between the SQUARELIST and the selected square roots are.

##### 7^{2} = 49 and 8^{2} = 64

Now we will take smaller one i.e. 7 and write 5 front of 7 so new value will be 75 and square the value i.e. 5625Now compare the values if 5625 < 5625

If the given question value is greater then square value then last digit of square root will be i.e. greater between both the value.Other wise take the smallest value i.e.

**5**.