Prbability

Vedic Maths trick to find Probability solutions

Q1 .Whta is the probability of getting a sum 8 from two throws of a dice?

probability = P (E)

Total event = n(S) = Fq = 62 = 36

where F = Faces of dice

q = Number of dice

( 1,1) ( 1,2) ( 1,3) ( 1,4) ( 1,5) ( 1,6) ( 2,1) ( 2,2) ( 2,3) ( 2,4) ( 2,5) ( 2,6) ( 3,1) ( 3,2) ( 3,3) ( 3,4) ( 3,5) ( 3,6) ( 4,1) ( 4,2) ( 4,3) ( 4,4) ( 4,5) ( 4,6) ( 5,1) ( 5,2) ( 5,3) ( 5,4) ( 5,5) ( 5,6) ( 6,1) ( 6,2) ( 6,3) ( 6,4) ( 6,5) ( 6,6)

Happening event = n(E) = 5

So Happening event = n(E) = 5 / 36

P(E) = n(E) / n(S)

P(E) = 5 / 36

P(E) = 5 / 36

So Probability of getting a sum 7 from two throws of a dice is 5 / 36