Q1 .Three unbiased coins are tossed .whta is the probability of getting atleast 2 heads?

probability = P (E)

Total event = n(S) = F^q = 2³ = 8

TTT TTH THT HTT THH HTH HHT HHH

As we see there are 4 times probability to get the atleast 2 heads

So Happening event = n(E) = 4

P(E) = n(E) / n(S)

P(E) = 4 / 8

P(E) = 1 / 2

Probability of getting atleast 2 heads is 1 / 2