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Q1 .In a box, there are
9
red ,
5
blue and
2
green balls.one ball is picked up randomely.what is the probability that it is neither red nor green.
probability = P (E)
Total event = n(S) = ( 9 + 5 + 2) = 16
Happening event = n(E) = 5
P(E) = n(E) / n(S)
P(E) = 5 / 16
P(E) = 5 / 16
Probability that it is neither red nor green balls is 5 / 16