Q1 .In a box, there are 9 red , 5 blue and 2 green balls.one ball is picked up randomely.what is the probability that it is neither red nor green.

probability = P (E)

Total event = n(S) = ( 9 + 5 + 2) = 16

Happening event = n(E) = 5

P(E) = n(E) / n(S)

P(E) = 5 / 16

P(E) = 5 / 16

Probability that it is neither red nor green balls is 5 / 16