Height And Distance

Height and Distance in just 10 second

Q .The Angle of elevation of a tower from a distance 37 m from its foot is 30° .Find the height of the tower.
A
B37mC

Let AB is a tower and Distance BC is 37 m so the elevation angle that is ∠C is 30° .

According to basic concept-


AB : BC : CA = 1 : √3 : 2

BC = √3 = 37m;

BC = √3 part = 37m;

AB = 1 part = 37m / √3

AB = 37m / √3 * √3 / √3

AB =37 * √3 m/ 3

AB =37 * 1.73m / 3 ( value of √3 = 1.73)

AB =21.336666666667 m

so Height of the tower is 21.336666666667 m.