Arithmetic Progression

Vedic Maths trick to find Arithmetic Progression.


Scenario One -

Find the sum of Arithmetic Progression : 4, 8, 12, 16, 20

Sn = Sum of nth term.
n = Number of terms.
Formula :
Sn = n ( n + 1 ) / 2
If nth term is multiple of any number then formula will be different
M = Multiple of number divisible by nth terms.
Formula :
Sn = M ( n ( n + 1 ) / 2 )

From above formula we will solve the given value.
Sn = 4 ( 5 ( 5 + 1 ) / 2 )
Sn = 60


Scenario Two -

Find the sum of Arithmetic Progression : 5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20

First we will find the Qth and Pth value from the given terms.
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20
Now from above terms we will find Qth and Pth value.

Qth = 4
Pth = 20
Now we will put above value in to formula given below
Sn = P(P+1)/2 - Q(Q+1)/2
Sn = 20 ( 20+ 1 ) / 2 - 4 ( 4+ 1 ) / 2
Sn = 210 - 10
Sn = 200